Two identical conducting spheres, fixed in place, attract each other with an electrostatic force of -0.2589 n when separated by 50 cm, center-to-center. the spheres are then connected by a thin conducting wire. when the wire is removed, the spheres repel each other with an electrostatic force of 0.3456 n. what were the initial charges on the spheres? since one is negative and you cannot tell which is positive or negative, there are two solutions. take the absolute value of the charges and enter the smaller value here. enter the larger value here.

Explanation:

Let the initial charge on the two spheres are

now we know that the force between them is given as

now when two spheres are connected then final charge on them is given as

now the force between them is given as

now we have

So by solving above two equations we have

your answer is, orbit around the nucleus

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards