Asailboat has a mass of 1.20 ✕ 103 kg and is acted on by a force of 2.90 ✕ 103 n toward the east, while the wind acts behind the sails with a force of 3.90 ✕ 103 n in a direction 45° north of east. find the magnitude (in m/s2) and direction (in degrees north of east) of the resulting acceleration.

a = 4.04 m/s2

north of east

Explanation:

The mass of the boat is m = 1200 kg

The forces acting  due to wind on the boat is Fwind = 3900 N j^ (north)

and The forces acting due to water  on the boat is Fwater = 2900 N i^ (east)

The net force on the boat is F = 2900 N i^ + 3900 N j^

The horizontal component of the net acceleration is ax = Fwater/m = 2.41 m/s2

vertical component of the net acceleration is ay = Fwind/m = 3.25 m/s2

Net acceleration is

a = 4.04 m/s2

The direction of the net acceleration is =

=north of east

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation: