Aball with a horizontal speed of 1.25m/s rolls off a bench 1.00m above the floor.

part a
how long will it take the ball to hit the floor?
part b
how far from a point on the floor directly below the edge of the bench will the ball land?

Part A: Time = 0.45 s

Part B: Horizontal distance = 0.5625 m

Explanation:

Part A:

       As the ball with a horizontal speed of 1.25 m/s rolls off a bench 1.00 m above the floor, it follow the projectile path.

Projectile motion is a two dimensional motion and the path followed by projectile motion is called projectile path.

Given data:

horizontal velocity = v₍ₓ₎ = 1.25 m/s

vertical velocity = v₍ₙ₎ = 0 m/s

Height = h = 1 m

From 2nd equation of motion

           h = v₍ₙ₎t + 0.5 gt²  

            1 = 0 + 0.5(9.81)t²

            2 = 9.81 t²

             t = √(0.2)

             t = 0.45 s

Part B:

        In projectile motion, horizontal component of velocity remain same,

So there is no acceleration in horizontal direction.

We can use the following formula

          Horizontal distance = R = v₍ₓ₎t

                                              R = 1.25 × 0.45

                                              R = 0.5625 m

e/c, where e is its total energy