The longest passenger liner ever built was the france, 66,348 tons and 315.5 long. suppose its front end passes the edge of a pier at a speed of 2.10 m/s while the ship is accelerating uniformly at 0.03 m/s^2. at what speed will the back end of the vessel pass the pier?

The back end of the vessel will pass the pier at 4.83 m/s

Explanation:

This is purely a kinetics question (assuming we're ignoring drag and other forces) so the weight of the boat doesn't matter. We're given:

Δd = 315.5 m

vi = 2.10 m/s

a = 0.03 m/s^2

vf = ?

The kinetics equation that incorporates all these variables is:

vf^2 = vi^2 + 2aΔd

vf = √(2.1^2 + 2(0.03)(315.5))

vf = 4.83 m/s

when insulating materials rub against each other, they may become electrically charged . electrons , which are negatively charged, may be 'rubbed off' one material and on to the other. the material that gains electrons becomes negatively charged. the material that loses electrons is left with a positive charge.

well, you would divide 135 by 33 to get your answer. then that is how many seconds it would take. boardman should fly about 132 m or 4.090909090909091 seconds.