Two projectile launchers are beside one another on level ground. both launchers are directed at the same angle with respect to ground. projectile a is launched with an initial speed v, and projectile bis launched with an initial speed 2v. how do the ranges of the two projectiles compare with one another? (a) projectile b will travel 4 times as far as projectile a prior to landing (b) projectile b will travel 3 times as far as projectile a prior to landing (c) projectile b will travel twice as far as projectile a prior to landing (d) projectile b will travel 2.5 times as far as projectile a prior to landing

(a) Projectile B will travel 4 times as far as projectile A prior to landing

Explanation:

Initial velocity = v

Angle at which the projectile is shot at = θ

g = Acceleration due to gravity

Range of a projectile is given by

When Initial velocity = v

When Initial velocity = 2v

Dividing the equtions, we get

Here, the angle at which the projectiles are fired at are equal.

Hence, projectile B will travel 4 times as far as projectile A prior to landing

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

0.55x745.7j and a calculator