What is the repulsive force between two pith balls that are 9.00 cm apart and have equal charges of -28.0 nc?

Force,

Explanation:

Given that,

Charges on pith balls,

Distance between balls, d = 9 cm = 0.09 m

Let F is the repulsive force between two pith balls. We know that the repulsive force between two charges is given by :

F = 0.000871 N

or

So, the repulsive force between the pith balls is . Hence, this is the required solution.

concave lenses are used here. they spread the light out before it reaches the convex lens in the eye, therefore letting the image focus directly on the retina. hyperopia is known to you probably as farsightedness.

the focus of lesson 1 is newton's first law of motion - sometimes referred to as the law of inertia. newton's first law of motion is often stated as. an object at rest stays at rest and an object in motion stays in motion with the same speed and in the same direction unless acted upon by an unbalanced force.

explanation: