In the return stroke of a typical lightning bolt, a current of 7.01×10^4 a (70.1 ka). exists for 20 μs. how much charge is transferred in this event ?

Charge, q = 1.402 C

Explanation:

Given that,

Current from lightning bolt,

Time, t =

Let q is the charge transferred in this event. We know that the total charge divided by time is called current. Mathematically, it is given by :

q = 1.402 C

So, 1.402 coulomb of charge is transferred in this event. Hence, this is the required solution.

the minimum amperage that the current in this wire would have to have so that its weight is completely supported by the magnetic force due to earth's field, assuming that no other forces except gravity act on it

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg