Consider two cylinders of gas identical in all respects except that one contains o₂ and the other he. both hold the same volume of gas at stp and are closed by a movable piston at one end. both gases are now compressed adiabatically to one-third their original volume. which gas will show the greater pressure increase?
a)it's impossible to tell from the information given.
b)the oxygen (o₂)
c)neither; both will show the same increase.
d)the he

D) He

Explanation:

For adiabatic change

\frac{P_2}{P_1} =(\frac{V_1}{V_2} )^\gamma

As the value of  \gamma increases, P_2 increases.

\gamma for He is 1.67 and \gamma for O₂ IS 1.4

Naturally The value  of P_2 is greater  for He. Increase in pressure for He is greater.

f=ma a/f/m a= 480/60 a = 8m/s/s that is quick wow

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer