Two boxes (24 kg and 62 kg) are being pushed across a horizontal frictionless surface, as the drawing shows. the 42-n pushing force is horizontal and is applied to the 24-kg box, which in turn pushes against the 62-kg box. find the magnitude of the force that the 24-kg box applies to the 62-kg box.

30.256 N

Explanation:

m = 24 kg

M = 62 kg

F = 42 N

Le a be the acceleration in the system and f be the contact force between both the blocks.

Use Newton's second law

F - f = m a (1)

f = M a (2)

Adding both the equations

F = (m + M) a

42 = (62 + 24) a

a = 0.488 m/s^2

Put the value of a in equation (2), we get

f = 62 x 0.488 = 30.256 N

i dont know but

explanation:

whoever your teacher is, deserves a raise for using pokemon as an example

pythagoras' theorem

square root (-5^2+9^2)

square root (25+81)

square root (106)

angle is tan^-1(9/5)

neg x, pos y