Aspeedboat increases its velocity from 25 m/s to
the west to 35 m/s to the west in a distance of 250 m.
a. find the magnitude of the boat's acceleration.

Magnitude of boat's acceleration is 1.2 ms⁻²

Explanation:

Given data

Initial velocity = v₁ = 25 m/s

Final velocity = v₂ = 35 m/s

distance = s = 250 m

Acceleration = a = ?

Using 3rd equation of motion

                       2 a s = v₂² - v₁²

          2 × a × (250) = 35² - 25²

                  500 × a = 600

                             a = 600/500

                             a = 1.2 ms⁻²

Thus the acceleration of the boat is 1.2 m/s² until it travel up to 250 m from initial velocity 25m/s to final velocity 35 m/s.

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