Two rockets are fired at each other with initial velocities of 150m/s150m/s and are 6000m6000m apart. the first rocket is accelerating at 5m/s25m/s2 while the second is accelerating at 15m/s215m/s2 . how far has the second rocket gone (in meters) when they collide? a :

3469.788 m

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

a = Acceleration

First rocket

Second rocket

When this will collide the total distance they would have covered would be 6000 m.

Hence at 13.72 seconds they will collide assuming they are launched at the same time.

The second rocket would have gone 3469.788 m when they collide

the old price per ounce is c/4.

the new price per ounce is c/3.6.

the ratio of the old price to the new one is

(c/4)/(c/3.6) = (c/c)×(3.6/4) = 0.9 . . = 9/10 . . "nine tenths" in either form