Asteel ball with mass m=5.21 g is moving horizontally with speed =412 m/s when it strikes a block of hardened steel with mass =14.8 kg (initially at rest). the ball bounces off the block in a perfectly elastic collision. (a) what is the speed of the block immediately after the collision? m/s ( ± 0.002 m/s) (b) what is the impulse exerted on the block?

a) The speed of the block immediately after the collision is .

b) The impulse exerted on the block is .

Explanation:

Hi

a) As this is a perfectly elastic collision, we can use the formula  , due , we obtain . Then with the data that we know and , therefore or adding uncertainty.

b) Now that we know the speed we can use

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