Ablock with mass m = 6 kg is sitting on a horizontal surface and not moving. the free-fall acceleration is g = 9.81 m/s2. answer the following questions.
a. write an expression for the magnitude of the force of gravity fg on the block.
b. calculate the magnitude of the force of gravity fg on the block in newtons.
c. in what direction is the force of gravity in this problem?
d. what is the magnitude of the normal force fn in newtons?
e. in what direction does the normal force act?

a. expression for force of gravity is mg

b. Value of force of gravity is 58.86 N

c. Direction of force of gravity is downwards

d. Value of normal force is -58.86 N

e. direction of normal force is upwards.

Explanation:

Given that mass of the block

acceleration due to gravity

a. Expression for force of gravity is

b.  

force of gravity is

c. Force of gravity always acts in the downward direction.

d. Normal force  acts in the direction opposite to the weight of the block and their magnitudes are same. since the object is at  rest the upward and downward forces on the block are balanced.

e. Normal force acts in the upwards.

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: