At summer camp, the swimming course runs the length (l) of a small lake. to determine the length of the course, the camp counselors measure the two "dry" legs of a right triangle. what is the length in meters of the swimming course in the figure below? a right triangle overlaps a lake. it has sides 25 and 40 meters. hypotenuse labeled l goes through the lake.

The length of the swimming course is 47.16 meters.

Explanation:

It is given that the right triangle overlaps the lake and hypotenuse L runs through the length of the lake. Thus length of the lake will be the length of this hypotenuse.

The instructors have conducted measurements of the right triangle and has found the legs to be 25 and 40 meters. The sum of squares of base and height of  a right triangle gives the value of its hypotenuse according to Pythagoras theorem.

Thus

b - base

h - height.

  distance on the y-axis and time on the x-axis.

explanation:

the instantaneous velocity = change in position/time taken

the slope of the graph should give instantaneous velocity.

  slope of a graph = change in value of y -axis / change in values of x -axis

  comparing both the equations

    change in value of y -axis = change in position

  change in values of x -axis = time taken

so position values should be on the y axis and time values should be on the x axis.

distance on the y-axis and time on the x-axis.

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft