Awater drop of mass 20g falls to the ground with a velocity of 8m/s from a height of 20m. what is the air resistance force acting on the water drop?

0.164 N

Explanation:

Newton's second law: sum of the forces equals mass times acceleration.

∑F = ma

F − mg = ma

a = (F − mg) / m

In real life, air resistance is a function of velocity.  But we will assume that it is constant.

Given:

y₀ = 20 m

y = 0 m

v₀ = 0 m/s

v = -8 m/s

Find: a

v² = v₀² + 2a (y − y₀)

(-8 m/s)² = (0 m/s)² + 2a (0 m − 20 m)

a = -1.6 m/s²

Therefore:

-1.6 m/s² = (F − 0.020 kg × 9.8 m/s²) / 0.020 kg

F = 0.164 N

Round as needed.

i guess that visual aids present persuasive examples to what you are presenting, some factors would be theme (does it fit with the color, information, what you are presenting), size (can you see it, is it a big enough span of data/information), and overall look of the visual aid.

hope this : )

6/12=1/2

step-by-step explanation: