Physics, 24.09.2019 16:30 tinasidell1972

Aball at rest falls from a platform above the ground. the ball falls freely and hits the ground 1.1s later. what is the height of the platform?

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Answer from: SandyRiverty

The height of the platform is 5.929 meters

Explanation:

- Free fall means that an object is falling freely with no forces acting on

it except gravity

- The height of the object is the distance from the point which the

object falls from it to the ground

The steps to solve the problem

1. Determine the acceleration of gravity

2. Decide whether the object has an initial velocity or not

3. Determine how long the object is falling

4. Calculate the height that the object falls from it

⇒ The gravitational acceleration g = 9.8 m/s²

The ball at rest falls from a platform above the ground

⇒ Initial velocity u = 0

The ball falls freely and hits the ground 1.1 s later

⇒ The time t = 1.1 s

We need to find the height (h) of the platform

The equation of the motion is h = u t + 1/2 g t²

⇒ h = u t + 1/2 g t²

⇒ u = 0 , t = 1.1 s , g = 9.8 m/s²

Substitute these values in the equation above

⇒ h = 0 + 1/2(9.8)(1.1)²

⇒ h = 5.929

The height of the platform is 5.929 meters

Answer from: mia2286

The height of the platform is 9.929 meters.

Given the following data:

Initial velocity = 0 m/s (since the ball starts from rest).Time = 1.1 seconds.

We know that acceleration due to gravity (a) of an object in free fall is equal to 9.8 meter per seconds square.

To find the height of the platform, we would use the following formula;

$H = \frac{1}{2}gt^2$

Substituting the parameters into the formula, we have;

$H = \frac{1}{2}(9.8)(1.1^2)\\\\H = 4.9(1.21)$

H = 4.9 × 1.21

Height, H = 9.929 meters.

Therefore, the height of the platform is 9.929 meters.

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Aball at rest falls from a platform above the ground. the ball falls freely and hits the ground 1.1s...

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