Tv channel 2 broadcasts in the frequency range 51 to 57 mhz. what is the corresponding range of wavelengths? (let us denote the minimum and maximum wavelengths by λmin and λmax, respectively.)

Explanation:

The frequency range of the TV channel,

We need to find the corresponding range of wavelengths. The relation between the frequency and the wavelength is given by :

For minimum frequency

For maximum frequency,

So, the corresponding wavelength range is from 5.88 m to 5.26 m. Hence, this is the required solution.

the answer is b ) square root of 5

true is the correct answer

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