Asoccer ball is released from rest at the top of a grassy incline. after 4.4 seconds, the ball travels 92 meters and 1.0 s after this, the ball reaches the bottom of the incline. what was the magnitude of the ball's acceleration, assume it to be constant? express your answer using two significant figures. a = nothing m/s2 request answer part b how long was the incline? express your answer using two significant figures. l = nothing m

The acceleration is 9.5 m / s

Explanation:

This problem can be handled as a one-dimensional case, if we place a coordinate system along the gram, in this case with the initial data we can calculate the acceleration; and the ball leaves the rest its initial speed is zero

      y = Vo t + ½ to t2

      y = ½ to t2

      a = 2 y / t2

      a = 2 92 /4.42

      a = 9.5 m / s2

The time or total to reach the bottom of the plane is

       t = 4.4 + 1 = 5.4 s

We calculate the distance traveled

       y= Vo t + ½ a t²

       y = ½  9.5  5.5²  

       y = 143 m = 14 x 101 m

lol

explanation:

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from wikipedia