Agas contained in a piston–cylinder assembly undergoes two processes, a and b, between the same end states, 1 and 2, where p1 = 1 bar, v1 = 1 m3, u1 = 400 kj and p2 = 6 bar, v2 = 0.167 m3, u2 = 420 kj: process a: constant-volume process from state 1 to a pressure of 6 bar, followed by a constant-pressure process to state 2. process b: process from 1 to 2 during which the pressure volume relation is pv = constant. kinetic and potential effects can be ignored. for each of the processes a and b, (a) evaluate the work, in kj, and (b) evaluate the heat transfer, in kj.

explanation:

newton's third law, for every action there is an equal and opposite reaction.

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.

unlike poles attract