A20 watt light bulb is left burning inside a refrigerator operating on a reverse carnot cycle. if the refrigerator also draws 20 watts of electrical power to operate its condenser, can it cool its interior below room temperature while the bulb is on? explain why or why not

Explanation:

Given that,

Power drawn by the refrigerator = 20 watt

Power of burning light inside = 20 watt

Room temperature = 27°C

We need to calculate the temperature

Using formula of coefficient of refrigerator

Put the value into the formula

is less than

Therefore, refrigerator cools its interior below room temperature while the bulb is on.

Hence, This is the required solution.

i think it's 35 meters

one person pulls 90n one way and the other has 100n pulling the other way.

so the net force = 90 - 100 = -10n,

or the ans can be 10n if the picture shows -90n and 100n instead.