Arear wheel drive car of mass 1000kg is accelerating with a constant acceleration without slipping from 0 to 60m/s in one minute. what will be the friction force on each rear wheel of the car?

Fs = 500 Newton

Explanation:

Given data:

Mass = 1000 kg

Initial speed = 0 m/s

By equation of motion we know that

v = u + at

Therefore a is = 1 m/s^2

From Newton's second law

where Fs is friction on each rear wheel

2Fs = 1000

Fs = 500 Newton

answer: decibel

explanation:

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s