Awheel initially spinning at wo = 50.0 rad/s comes to a halt in 20.0 seconds. determine the constant angular acceleration and the number of revolutions it makes before stopping. an athlete is holding a 2.5 meter pole by one end. the pole makes an angle of 60 with the horizontal. the mass of the pole is 4 kg. determine the torque exerted by the pole on the athlete's hand. (the mass of the pole can be assumed to be concentrated at the center of mass.)

part (a)

part (b) N = 79.61 rev

part (c)

Explanation:

Given,

part (a)

Let be the angular acceleration of the wheel.

Wheel is finally at the rest. Hence the final angular speed of the wheel is 0.

part (b)

Let be the total angular displacement of the wheel from initial position till the rest.

We know,  1 revolution = rad

Let N be the number of revolution covered by the wheel.

Hence the 79.61 revolution is covered by the wheel in the 20 sec.

part (c)

Given,

Now the center of mass of the pole =

Weight component of the pole perpendicular to the center of mass =

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find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle