If a ball is thrown straight up into the air with an initial velocity of 65 ft/s, its height in feet after t seconds is given by f(t)=65t−16t2 find the average velocity for the time period beginning when t=2 and lasting (i) 0.5 seconds 61.5 (ii) 0.1 seconds 65.74 (iii) 0.01 seconds 65.98 (iii) 0.001 seconds 65.99 based on the above results, guess what the instantaneous velocity of the ball is when t=2.