Acharge located at (3,-5) in the x-y plane exerts an attractive force of 0.75n on another charge located at (2,7) (all distances are in cm) a) in what direction does this force point? the answer should be given as a counterclockwise angle with respect to the positive x-axis. b) write down an expression for this force in terms of unit vectors i and (don't forget your units). c) if the charge at (3,-5) is +2pic, determine the magnitude and sign of the other charge.

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j