Two small spherical insulators separated by 2.5 cm, which is much greater than either of their diameters. both carry positive charge, one +60.0 microcoulombs and the other +6.66 microcoulombs. a third positive charge remains at rest between the two spheres and along the line joining them. what is the position of this charged sphere?

The third charge is placed at a distance of 1.88 cm  from the centre of 60 micro coulombs charge to the right of it.

Explanation:

Given:

Distance between the centre of insulators=d=2.5 cm

Charge on insulator(1`)= 60

Charge on insulator(2`)= 6.66

Let third charge be placed at a distance of x xm from the centre of 60 charge.

Now according to coulombs law the force between tow charges placed at distance r is given by

Let magnitude of third charge be q and it placed at a distance of x from  higher magnitude charge. According to question the net force on third charge is zero so we have

.

Hence the position of third charge is calculated in order to be rest.

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explanation:

a

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