The captain of a plane wishes to proceed due west. the cruising speed of the plane is 256 m/s relative to the air. a weather report indicates that a 44.3-m/s wind is blowing from the south to the north. in what direction, measured with respect to due west, should the pilot head the plane?

Angle = 9.965° South of West.

In the question,

The speed of the Plane w.r.t to Wind = 256 m/s

Speed of the Wind w.r.t to Ground = 44.3 m/s

Direction of Wind = North from South

Direction Plane wishes to go = West

So,

Using the vectors,

Speed of Wind w.r.t Ground is given by,

Resultant speed of Plane w.r.t Ground is given by,

So,

From the Vector's Triangle Sum property,

Therefore, the plane has to move in the direction of 'III quadrant' or 'South-West' direction.

Now,

In the triangle, using Pythagoras Theorem,

The speed of the plane = 252.13 m/s

Now,

Therefore, the angle at which the plane should fly to go West is = 9.965° South of West.

f=ma newton's second law 7x8=56n

unbalanced force

explanation: