We want to hydrolyze 500 lb per day of an ester at an initial concentration of 5 m (the ester has a molecular weight of 130) in aqueous basic solution in a batch process, and we need product that is 99% hydrolyzed. in benchtop experiments in a flask, we find that 50% of the ester hydrolyzes in 15 min for initial ester concentrations of either 1 or 5 m. we also find that, when we react for 8 h, all of the ester has hydrolyzed. it takes 1 h to empty the reactor and refill and heat it to start another batch. what size reactor will we need?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

Answer ( slope);

The answer is mean don't know