Suppose that a photoelectric experiment is conducted using two lasers, one tuned to 450 nm(blue)output and the other tuned to 560 nm (yellow) output. both frequencies exceed the work function, φ= 1.62 ev, of the metal. assuming the number of photons delivered by each laser is the same, which light would generate more electrons? which light would eject electrons with greater kinetic energy?

Both  laser  produce the same number of electrons.

The blue light produces electron with higher kinetic energy.

Explanation: Taking into account the energy conservation for the photoelectric  effect

we have :

Ek ( kinetic energy) = E Photon ( phonon energy)- Fi ( work function)

E Photon = 1240/wavelenght (nm)

multiply 2kg by latent heat of vap

hi there!

out of the two, (b) precision would be more reasonable.   however, both a and b could be pretty reasonable.

-awesomerepublic   : )