Aparticle of charge q is fixed at the origin of an xy coordinate system. at t = 0 a particle (m = 0.693 g, q = 3.09 µc is located on the x axis at x = 24.6 cm, moving with a speed of 74.0 m/s in the positive y direction. for what value of q will the moving particle execute circular motion? (neglect the gravitational force on the particle.)

33.57μC

Explanation:

The moving particle will execute a circular motion when the Electric force between the particles is equal to the centripetal force necessary for the circular motion at a velocity equal to 74m/s and a radius = 0.246m. You can find the value for the centripetal force with this expression:

Now, this is the value that the electric force between the charges should be. The electric force is given by this expresion:

k is the Coulomb constant, equal to 9*10^9 Nm^2/C^2. Then:

Or 33.57μC

12000j is work done

e

explanation:

there is no change in the electric potential energy as it is in rest on both conditions.