Calculate the minimum kinetic energy of the incident proton that will allow this reaction to occur if the second (target) proton is initially at rest. the rest energy of each kaon is 493.7 mev, and the rest energy of each proton is 938.3 mev. (hint: it is useful here to work in the frame in which the total momentum is zero. note that here the lorentz transformation must be used to relate the velocities in the laboratory frame to those in the zero-total-momentum frame.)

i was thinking more like reflects green light, just not sure

force tends to be low and long diustance masses are high

as we know our atmosphere or air have different levels. every level has other gasses, and every gas has another permeability. when the light comes from lower permeability to higher permeability, it changes its direction. so that means that when the light comes from the moon to the earth, it changes it's direction many more times. it basically means that the shape of the light part of the moon is changed on the earth.

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