The width, length, and height of a large, custom-made shipping crate are 1.12 m, 1.25 m, and 0.83 m, respectively. the volume of the box using the correct number of significant figures is m3. the width, length, and height of a large, custom-made shipping crate are 1.12 m, 1.25 m, and 0.83 m, respectively. the volume of the box using the correct number of significant figures is m3. 1.16 1.2 1.1620 1.162 1.16200

1.16 .

Explanation:

In the  product of two or more physical quantities , the number of places after decimal in the result  can never be more than least number of place after decimal in the quantities that are being multiplied .

Here numbers that are being multiplied are ,

1.12 , 1.25, and .83 , each containing two digits after decimal . So the product can not contain more than two digits after decimal . The principle behind it is that the result can not have more precision than the precision of  amount that are being multiplied.

so

1.12 x 1.25 x .83 = 1.162 to be rounded off to 1.16 .

The answer is 1.16.

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.

the small 0.38-kg slider is known to move from position a to position b along the vertical-plane slot. determine (a) the work done on the body by its weight and (b) the work done on the body by the spring. the distance r = 0.70 m, the spring modulus k = 154 n/m, and the unstretched length of the spring is 0.53 m

explanation:

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