30) a foul ball is hit straight up into the air with a speed of 30.0 m/s. (a) calculate the time required for the ball to rise to its maximum height. (b) calculate the maximum height reached by the ball. (c) determine the time at which the ball pass a point 25.0 m above the point of contact between the bat and ball. (d) explain why t

a) 3.05 seconds

b) 45.87 m

c) 0.995 seconds

Explanation:

t = Time taken

u = Initial velocity = 30 m/s

v = Final velocity = 0

s = Displacement

a = Acceleration = 9.81 m/s² (positive downward, negative upward)

a) Time taken by the ball to reach maximum height

Time taken by the ball to reach maximum height is 3.05 seconds

b) Maximum height

Maximum height reached by the ball is 45.87 m

c) If s = 25 m

Velocity of the ball at 25 m height is 20.24 m/s

Time taken by the ball to reach a point 25.0 m above the point of contact between the bat and ball is 0.995 seconds

no. dot product   =0 when vecs at right angles