Aball is dropped from the top of a building that is known to be 400 feet high. the formula for finding the height of the ball at any time is h=400−16t2, where t is measured in seconds.
how many seconds did it take for the ball to reach a height of 256 feet above the ground?

3 seconds

Explanation:

Height of the building = 400 feet

Height of the ball from the ground is given by

h=400−16t²

This formula has been derived from

a = Acceleration due to gravity = 32 ft/s²

u = Initial velocity = 0

t = Time taken

Substituting all the values we get

This is the height of the ball from the top of the building

The height of the ball from the ground will be

h = 400-s

⇒h = 400−16t²

When h = 256 ft

Time taken by the ball to reach a height of 256 feet above the ground is 3 seconds

1/0.14nm = 10^10/1.4 a lot

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