Abar membrane walls of living cells have surprisingly large electric fields across them due to separation of ions. what is the voltage across an 8.67-mm-thick membrane if the electric field strength across it is 8.36 mv/m? you may assume a uniform e-field. v helium nucleus has two positive charges and a mass of 6.64 10-27 kg. (a) calculate its kinetic energy in joules at 7.30% of the speed of light.

Part a)

Part b)

Explanation:

As we know that the electric field between the membrane is given as

here the distance between two membranes is given as

now we know that potential difference between two membranes is given as

so we have

Part b)

Kinetic energy of helium nucleus is given as

so we have

inverse v=i*r

nice nice

96.77 amp

explanation:

rl = 250/100 = 2.5 ohms.

egl = 250 + (100 × 0.1) + 2 = 262 v.

at 700 r.p.m., eg2 = 262 × 700/1000 = 183.4 v.

if ia is the new current, then eg2 - 2 - (ia × 0.1) = 2.5 ia

which means this will give ia = 96.77 amp.