If the fundamental frequency of a piece of conduit is 707 hz, and the speed of sound is 343 m/s, determine the length of the piece of conduit (in m) for each of the following cases. (a) the piece of conduit is closed at one end (b) the piece of conduit is open at both ends

i)0.1213m

ii)0.2426 m

Explanation:

The formula to apply here are;

For a closed conduit at one end the fundamental frequency produced by a pipe of length L is ;

f=v/4L where v is speed of sound and L is length of conduit

707=343/4L

707*4L=343

2828L=343

L=343/2828

L=0.1213m

For an open conduit, the fundamental frequency produced by pipe of length L is given by;

f=v/2L where v is speed of sound and L is length of conduit

707=343/2L

707*2L=343

1414L=343

L=343/1414

L=0.2426 m

here we know that ball will drop down by total distance 3.2 m

so here we know that

now using kinematics

now in the same time it will cover horizontal distance of 0.75 m

so speed of the ball will be