Aball is batted straight up into the air and reaches a maxium height 65.6 m (a) how long did it take to reach this height? (b) what was the pop-up velocity of the ball?

a) 3.65 seconds

b) 35.87 m/s

Explanation:

s = Displacement = 65.6 m

u = Initial velocity

v = Final velocity

t = Time taken

a = Acceleration due to gravity = 9.81 m/s² (downward direction is taken as positive and upward is taken as negative)

b) Equation of motion

Initial pop up velocity is 35.87 m/s

a)

It took 3.65 seconds to reach this height

it is b. absorbs thermal energy

you get 2.3=1.21*\frac{a}2 or 4.6=1.21a or a=3.802 (b)

explanation: