You have two square metal plates with side length of 16.50 cm. you want to make a parallel-plate capacitor that will hold a charge of 18.5 nc when connected to a 37.8 v potential difference. determine the necessary separation in mm. round your answer to three significant figures.

d = 3.44 *10^{-7} m  

Explanation:

given data:

length of metal plates = 16.50 cm

capacitor charge = 18.5 nC

potential difference = 37.8 V

capacitance of parallel plate capacitor

area of the individual plate

A= m2

capacitance

separation between plates d  is given as

d = 3.44 *10^{-7} m  

does anyone know or what?