Apendulum on earth has a period of 1.2 seconds. the same pendulum on mercury (dark side) has a period of 1.95 seconds. what is the free-fall acceleration of mercury (in m/s^2)

Explanation:

Given that,

Time period of a pendulum on the earth's surface, T₁ = 1.2 s

Time period of the same pendulum on Mercury, T₂ = 1.95 s

The time period of the pendulum is given by :

On earth :

.............(1)

Let g' is the acceleration due to gravity on Mercury. So,

............(2)

From equation (1) and (2) :

So, the acceleration due to gravity on the mercury is . Hence, this is the required solution.

we need some answer choices, or something like that

explanation:

d) the number of neutrons plus the number of protons