Determine the solution for the pure diffusion problem, )= 0, for a one-dimensional material that has a variable conductivity, k=k, +at. the material has a constant area, a, and is of length x = l. this problem is non-linear as the conductivity is dependent on the temperature and must be solved iteratively for a local volume, find the exact integral form of the governing equation 1. apply the linear approximation for an internal cell surrounded by two neighbours 2. for this problem, the essential boundary condition (also known as dirichlet condition) is imposed at 3. l. determine the appropriate approximation formulae for the boundary nodes. x 0 and solve the problem for l = 0.5, t(x =0) =100, t(x l) 500,k, =1000, a =10 using 100 cells. to 4. solve, you need to modify the code and here is the suggested algorithm, input data a. b. initialize temperature in the domain using the linear solution, t(x) = t{0) t(l)-t(0) x l and call the solution t_1, then evaluate the conductivity k = k, +oat_1 accordingly start outer iteration loop (you can set it to 50 iterations) c. i. evaluate the coefficients ag, a,.a, b, for boundary cell at x 0 and fill in first row in matrix evaluate the coefficient ag. ap, a,b, for interior cells and fill in the rows 2 ii. n-1 evaluate the coefficients ag, ap, aw, b, for boundary cell at x= land fill in last row iii in matrix solve to determine the temperature distribution, call the solution t 2 iv. evaluate the difference (residual) t_2-t_1 and evaluate the norm. save the norm at v. each iteration rename the solution t_2 as t_1 vi. evaluate the conductivity k =k, +at_1 and repeat from (i) vii. plot the final solution t(x) and the euclidean norm of the residual d.

i think it’s a. this is because if they measured the mass of something with a mass of 150g, then their final answer would have to be approximately 150g. though all of their answers are almost 150, rosa and tran have the closest answers (or the exact answer) to the accurate one.

emily ruth's annual premium is $1058.50

step-by-step explanation:

emily ruth is a female of 27 years age purchasing 20 year endowment insurance with face value $25000.

from the given table,

for females, the age of a male 3 years younger should be used.

so, we have to check for 24 year male for 20 year endowment.

it is 42.34 for every $1000 face value.

for a face value of $25000,

it is 25 * 42.34 = $1058.50

∴ emily ruth's annual premium is $1058.50

bacteria that live on the ocean floor are sustained by phytoplankton. phytoplankton, microscopic marine photosynthetic organisms, have a vastly significant role to play not only in the marine food web of which they’re part of, but also on a more global scale. despite their infinitely small size in comparison to other marine organisms, these tiny creatures occupy an immensely important ecological niche: they are the foundation of the marine food web, and as primary producers, play key roles in supporting all other organisms in the marine environment, as well as in the regulation of the earth’s climate through the sequestration of carbon, oxygen production, and other related processes. phytoplankton account for roughly half of all global primary productivity; therefore, their significance extends far beyond the marine environment alone. there is an intriguing sense of irony in the realization that these tiny living beings that often live out their existence unnoticed and undetected by the rest of the world, have such a far-reaching impact on the lives of virtually all other living organisms on the planet, particularly on those in the marine environment. the world that we have become accustomed to has been and is continuously shaped by the workings of these miniscule yet vital “plants of the sea”.

hope this !