(modified from anderson, question 1.1) consider the supersonic and hypersonic flow of air (with constant ratio of specific heats, y=1.4) over a 2-d wedge with a half-wedge angle of 20 degrees. let e denote the half-wedge angle and ß the shock wave angle. then ß - 0 is a measure of the shock layer thickness. a. make a plot of ß – 0 vs. the free-stream mach number m. from mo = 2 to 20. make some comments as to what mach number range results in a thin shock layer? b. plot the static pressure ratio, static temperature ratio, and the static density ratio across the shock for the same mach number interval considered in part a. c. would you expect to get a smaller or larger shock layer thickness if you have considered real gas effects (i. e., chemical reactions) for the mach number range you have determined in part (a) resulting a thin shock layer. explain your reasoning.

the expression 15n + 2(3p) represents the amount isaiah spent buying gasoline and snacks, where n represents the price of each gallon of gasoline and p represents the cost of each snack that he bought. which statement is true about the amount isaiah spent?

most voltage drop calculators want the distance between the source and destination. then internally, they double it so both the source and return wires are calculated. but you need to know which distance the calculator uses so you're not half of what you should be or double what you should be.

most circuit breakers will not take a #6 directly, so the electrician will have to splice on a smaller pigtail. you also have to upsize the grounding wire when you upsized the ungrounded (hot) wire (see note in 250.122). this will preclude using most cable assemblies, as a cable with #6 copper will most likely only have a #10 grounding conductor. you need a #6 grounding conductor if the circuit is 20a. a #8 cable is no better, as it will have a #10 grounding conductor too. but most 20a breakers will take a #8 directly.

in your related post, you didn't say what type of load this is. if it is a light or heater, voltage drop won't be a big issue. if this is a motor, the current needs are huge at startup and the voltage drop can pose a problem. if this is a motor, knowing if the motor is under much load during startup will answer the voltage drop effect (a saw is easier to start than a compressor).

hey , the answer is c

the displacement produced by the body.  

the amount of force subjected to the body.  

the angle between the direction of force and displacement