Acharge q1= 3nc and a charge q2 = 4nc are located 2m apart. where on the line passing through these charges is the total electric field zero?

Explanation:

Electric field due to a charge Q at a point d distance away is given by the expression

E = k Q / d , k is a constant equal to 9 x 10⁹

Field due to charge = 3 X 10⁻⁹ C

E = E =

Field due to charge = 4 X 10⁻⁹ C

These two fields will be equal and opposite to make net field zero

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These two fields will be equal and opposite to make net field zero

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d = 0.928

speed

ratio of distance traveled to time interval

net force

vector sum of forces on object

object

source of diverging light rays either luminous or illuminated

don't remove my answer im trying my best to answer them

explanation:

1/0.14nm = 10^10/1.4 a lot