Acheetah running at 17.5 m/s looses its prey and begins to slow down at a constant acceleraton, fianlly stopping 30.5 m later. how long does it take the cheetah to come to rest and what is the cheetah's acceleration while doing so? i know the answer which is ∆t= 3.49 s but want to see the work how it gets 3.49 s.

Explanation:

As we know that initial speed of the cheetah is given as

finally it comes to rest so final speed is given as

now we know that distance covered by cheetah while it stop is given as

now by equation of kinematics we know that

here we have

Now in order to find the acceleration we know that

jupiter is the largest planet in our solar system, having a mass and radius that are respectively, 318 and 11.2 times that of earth. suppose that an object falls from rest near the surface of each planet and that the acceleration due to gravity remains constant during the fall. each object falls the same distance before striking the ground. determine the ratio of the time of fall on jupiter to that on earth.

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.