Aaron was challenged to kick a soccer ball off of the flat roof of the science building and into a trashcan 12.3 m away from the edge of the building. the science building is 11.3 m tall. since this is unsafe, aaron suggested that he works it out on paper instead. assuming the ball is kicked off the building with only a horizontal velocity, how fast would the ball need to leave the top of the building to land in the trash can?

8.1 m /s

Explanation:

Let the required velocity be v . This is a horizontal velocity so it will cover the horizontal distance of 12.3 m with this velocity without any acceleration .

Time taken t = distance / velocity

t = 12.3 /v

During this period ball also covers vertical distance with initial velocity zero and acceleration of g.

For vertical fall

initial velocity u = 0

Acceleration = g

Time = t

h = ut + 1/2 g t²

11.3 = 0 + .5 x 9.8 x (12.3 / v )²

v² = 65.6

v = 8.1 m /s

most of them using statistics and defining how things are being measured

i believe the answer is a