The position of a particle in millimeters is given by s = 133 - 26t + t2 where t is in seconds. plot the s-t and v-t relationships for the first 19 seconds. determine the net displacement as during that interval and the total distance d traveled. by inspection of the s-t relationship, what conclusion can you reach regarding the acceleration?

Answer with Explanation:

The position of the particle as a function of time is given by

Part 1) The position as a function of time is shown in the below attached figure.

Part 2) By the definition of velocity we have

The velocity as a function of time is shown in the below attached figure.

Part 3) The displacement of the particle in the first 19 seconds is given by

Part 4) The distance covered in the first 19 seconds can be found by evaluating the integral

Part 4) As we can see that the position-time graph is parabolic in shape hence we conclude that the motion is uniformly accelerated motion.

mistakes are ok

v=ir = 3x15 =45 v