Two 2.4 cm -diameter disks face each other, 1.0 mm apart. they are charged to ±11nc. what is the electric field strength between the disks?

Explanation:

Given:

The surface area of each of the disc is given by

For the case, when d<<D, the strength of the electric field at a point due to a charged sheet is given by

where,

The electric field strength between the discs due to negative disc is given by

Since, the electric field is directed from positive charge to negative charge, therefore, the direction of this electric field is towards the negative disc.

The electric field strength between the discs due to positive disc is given by

The direction of this electric field is away from the positive disc, i.e., towards negative disc.

The electric field between the discs due to both the disc is towards the negative disc, therefore the total electric field strength between the discs is given by

answer: the correct answer id option(d).

explanation:

snell's law refraction:

the angle of refraction =

the angle of incidence =

refractive index of air = = 1

refractive index of glycerol = 1.47

from the given options, the most closest answer to 63.72° is 65° of option (d).

answer: 31, 5556. 952 seconds