Agray kangaroo can bound across level ground with each jump carrying it 9.1 m from the takeoff point. typically the kangaroo leaves the ground at a 26° angle. if this is so: 1) what is its takeoff speed
2) what is its maximum height above the ground?

u = 10.63 m/s

h = 1.10 m

Explanation:

For Take-off speed ..

by using the standard range equation we have

R = 9.1 m

θ = 26º,

Initial velocity = u

solving for u

u = 10.63 m/s

for Max height

using the standard h(max) equation ..

h = 1.10 m

low freq = 100 mhz

low wavelength =101.7m

length = 3x10^8/freq