Mary's glasses have +4.4d converging lenses. this gives her a near point of 20cm. what is the location of her near point when she is not wearing her glasses?
express your answer with the appropriate units.

The position of near point is 1.68 m.

Explanation:

Given that,

Power = + 4.4 D

Object distance = 20 cm

We need to calculate the focal length

Using formula of power

We need to calculate the image distance

Using formula of lens

Put the value into the formula

Hence, The position of near point is 1.68 m.

electrical potential energy =0.072 j

explanation:

electrical potential energy is given by

u= q δv

q= charge=6 c

δv= potential difference and is given by

δv= e d

e= electric field

d= distance=5 mm=0.005 m

δv=2.4 (0.005)=0.012 v

now electric potential energy= u= q δv

u=6 (0.012)

u=0.072 j

no

explanation:

no i dont know how to solve this you should probably try to google the answer