What are the sign and magnitude of a point charge that produces an electric potential of −2.36 v at a distance of 2.93 mm?

q = -7.691 × C

so magnitude of charge is 7.691 × C

and negative sign mean charge is negative potential

Explanation:

given data

electric potential = −2.36 V

distance = 2.93 mm = 2.93 × m

to find out

What are the sign and magnitude of a point charge

solution

we know here that electric potential due to charge is

V =       ..............................1

here k is coulomb force that is 8.99 × Nm²/C² and r is distance and q is charge  and V is electric potential

put here all value we get q  in equation 1

V =

-2.36 =

q = -7.691 × C

so magnitude of charge is 7.691 × C

and negative sign mean charge is negative potential

energy can be converted from one form to another, but it cannot be created or destroyed in ordinary chemical or physical means. do not understand what you are asking but hope this

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg