Asolid conducting sphere of radius 2.00 cm has a charge of 6.88 μc. a conducting spherical shell of inner radius 4.00 cm and outer radius 5.00 cm is concentric with the solid sphere and has a charge of −2.96 μc. find the electric field at the following radii from the center of this charge configuration. (a) r = 1.00 cm magnitude: n/c
direction:
(b) r = 3.00 cm magnitude: n/c
direction:
(c) r = 4.50 cm magnitude: n/c direction:
(d) r = 7.00 cm magnitude: n/c
direction:

Explanation:

Given that,

Radius R= 2.00

Charge = 6.88 μC

Inner radius = 4.00 cm

Outer radius  = 5.00 cm

Charge = -2.96 μC

We need to calculate the electric field

Using formula of electric field

(a). For, r = 1.00 cm

Here, r<R

So, E = 0

The electric field does not exist inside the sphere.

(b). For, r = 3.00 cm

Here, r >R

The electric field is

Put the value into the formula

The electric field outside the solid conducting sphere and the direction is towards sphere.

(c). For, r = 4.50 cm

Here, r lies between R₁ and R₂.

So, E = 0

The electric field does not exist inside the conducting material

(d).  For, r = 7.00 cm

The electric field is

Put the value into the formula

The electric field outside the solid conducting sphere and direction is away of solid sphere.

Hence, This is the required solution.

find the sum of the two horizontal vectors and the sum of the two vertical vectors

isoceles right angled triangle

in order to follow the instructions and complete the statements, i need to use data from table c of your student guide. can you think of a way to let me see your student guide for a while ? i can't answer the question without the data in table c.