Ataxi traveling along a straight section of road starts from rest, accelerating at 2.00 m/s2 until it reaches a speed of 27.0 m/s. then the vehicle travels for 41.0 s at constant speed until the brakes are applied, stopping the vehicle in a uniform manner in an additional 5.00 s. (a) how long is the taxi in motion (in s)? s (b) what is the average velocity of the taxi for the motion described? (enter the magnitude in m/s.) m/s

Part a)

Part b)

v = 22.8 m/s

Explanation:

Part a)

Time taken by the taxi to reach the maximum speed is given as

now it moves with constant speed for next 41 s and then finally comes to rest in next 5 s

so total time for which it will move is given as

Part b)

Distance covered by the taxi while it accelerate to its maximum speed is given as

Now it moves for constant speed for next 41 s so distance moved is given as

Finally it comes to rest in next 5 s so distance moved in next 5 s

so here we have total distance moved by it is given as

average speed is given as

answer: 2×10^-2kg

explanation: density= mass per volume

vol=mass/density

converting to s.i units we have;

3÷1000kg = 0.003

1.5÷100m = 0.15

0.003/0.15 = 0.02kg

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards